How do I get a NamedSelection by name in Mechanical?

Landon Mitchell Kanner

I would like a script that takes the name of a NamedSelection as input and returns the NamedSelection

Landon Mitchell Kanner

def GetNSbyName(name,AcceptPartial = False):
	    try:
	        NSs = ExtAPI.DataModel.Project.Model.NamedSelections.Children
	    except:
	        return None
	    for ns in NSs:
	        if ns.Name.ToLower() == name.ToLower():
	            return ns
	        if AcceptPartial and  (name.ToLower() in ns.Name.ToLower()):
	            return ns
	    ExtAPI.Log.WriteWarning("Named Selection not found: "+str(name))
	    return None

Pavel

This function:

def ns_by_name(ns_name):
    return [o for o in DataModel.GetObjectsByType(DataModelObjectCategory.NamedSelection) if o.Name == ns_name]

• case sensitive
• Returns list matching any named selections matching the name, if you want the first one just add [0] at the end ns_by_name('name')[0] or have it return 1st member altogether. Returning list is best because no checking is needed and it's simple.

James Derrick

Hi @Landon Mitchell Kanner Can you include the code in your post? It is best practice to avoid just linking to external resources because the answer is quite fragile and depends on the link's persistence, as well as user access. For example, if that GitHub repo goes private next week, then people won't be able to check out GetNSbyName.

Landon Mitchell Kanner

Combining both answers (untested):

def GetNSbyName(name,AcceptPartial = False):
  NSs = DataModel.GetObjectsByType(DataModelObjectCategory.NamedSelection)
  if AcceptPartial:
    return [ns for ns in NSs if name.ToLower() in ns.Name.ToLower()]
  else:
    return [ns for ns in NSs if ns.Name.ToLower() == name.ToLower()]