How to get Von Mises equivalent stresses in a random vibration analysis using DPF?

Javier Vique
Javier Vique Member, Employee Posts: 84
5 Answers 25 Likes 10 Comments First Anniversary
✭✭✭✭
edited June 2023 in Structures

If we try to use stress_von_mises results, we are getting different values than Mechanical. Why?

Tagged:

Answers

  • Javier Vique
    Javier Vique Member, Employee Posts: 84
    5 Answers 25 Likes 10 Comments First Anniversary
    ✭✭✭✭

    As you might know, for getting Von Mises equivalent stresses we make use of Segalman formulation. That's why we need to make use of that operator to get same results as Mechanical. Below the script to be used:

    def define_dpf_workflow(analysis):
    import mech_dpf
    import Ans.DataProcessing as dpf
    mech_dpf.setExtAPI(ExtAPI)
    dataSource = dpf.DataSources(analysis.ResultFileName)
    timeScoping = dpf.Scoping()
    timeScoping = [2]
    s = dpf.operators.result.stress()
    s.inputs.data_sources.Connect(dataSource)
    s.inputs.time_scoping.Connect(timeScoping)
    s.inputs.requested_location.Connect('ElementalNodal')
    op = dpf.operators.invariant.segalman_von_mises_eqv_fc()
    op.inputs.fields_container.Connect(s.outputs.fields_container)
    my_fields_container = op.outputs.fields_container
    dpf_workflow = dpf.Workflow()
    dpf_workflow.Add(op)
    dpf_workflow.SetOutputContour(my_fields_container)
    dpf_workflow.Record('wf_id', False)
    this.WorkflowId = dpf_workflow.GetRecordedId()

Categories