I want to get the path of the currently open [dsco] file in the Discovery script.

I want to get the path of the currently open [dsco] file in the Discovery script, but
which class or method should I use?

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What are you trying to do with it? You simply could import the os module and use the getcwd (cwd=current working directory)

import os
currentPath = os.getcwd()

Thank you for your response.

My question was not clear. When executing a script embedded in a dsco file, I want to obtain the directory path of that dsco file.

When executing with “os.getcwd()” embedded, the installation folder of “Discovery” is obtained, so I am looking for another method.

I appreciate your help and look forward to your advice.

Best regards,
Shin

Please try
GetActiveWindow().Document.Path