How to include deformation scaling into a plot created by Python Result? By default it is unscaled

Rohith Patchigolla
Rohith Patchigolla Member, Moderator, Employee Posts: 242
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in Structures

By Adjusting Deformation scaling in Mechanical, one could scale the Deformed shape for any standard result. But, this doesn't seem to work for Python Result (scaling is greyed out).

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  • Rohith Patchigolla
    Rohith Patchigolla Member, Moderator, Employee Posts: 242
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    edited August 2024

    One would just need to add the below line to the default code when one inserts Python result to deform the plot based on Deformation scaling.

    dpf_workflow.SetOutputWarpField(u)

    def post_started(sender, analysis):# Do not edit this line
    define_dpf_workflow(analysis)

# Uncomment this function to enable retrieving results from the table/chart
# def table_retrieve_result(value):# Do not edit this line
    # import mech_dpf
    # import Ans.DataProcessing as dpf
    # wf = dpf.Workflow(this.WorkflowId)
    # wf.Connect('contour_selector', value)
    # this.Evaluate()

def define_dpf_workflow(analysis):
    import mech_dpf
    import Ans.DataProcessing as dpf
    mech_dpf.setExtAPI(ExtAPI)
    dataSource = dpf.DataSources(analysis.ResultFileName)
    u = dpf.operators.result.displacement()
    nrm = dpf.operators.math.norm_fc()
    # timeScop = dpf.Scoping()
    # timeScop.Ids = [1]
    # u.inputs.time_scoping.Connect(timeScop)
    u.inputs.data_sources.Connect(dataSource)
    nrm.Connect(u)
    dpf_workflow = dpf.Workflow()
    dpf_workflow.Add(u)
    dpf_workflow.Add(nrm)
    dpf_workflow.SetOutputWarpField(u)
    # dpf_workflow.SetInputName(u, 0, 'time')
    # dpf_workflow.Connect('time', timeScop)
    dpf_workflow.SetOutputContour(nrm)
    dpf_workflow.Record('wf_id', False)
    this.WorkflowId = dpf_workflow.GetRecordedId()

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