How to include deformation scaling into a plot created by Python Result? By default it is unscaled

Rohith Patchigolla
Rohith Patchigolla Member, Moderator, Employee Posts: 212
100 Comments 25 Answers Second Anniversary 25 Likes
✭✭✭✭
in Structures

By Adjusting Deformation scaling in Mechanical, one could scale the Deformed shape for any standard result. But, this doesn't seem to work for Python Result (scaling is greyed out).

Tagged:

Answers

  • Rohith Patchigolla
    Rohith Patchigolla Member, Moderator, Employee Posts: 212
    100 Comments 25 Answers Second Anniversary 25 Likes
    ✭✭✭✭
    edited August 8

    One would just need to add the below line to the default code when one inserts Python result to deform the plot based on Deformation scaling.

    dpf_workflow.SetOutputWarpField(u)

    def post_started(sender, analysis):# Do not edit this line
    define_dpf_workflow(analysis)

# Uncomment this function to enable retrieving results from the table/chart
# def table_retrieve_result(value):# Do not edit this line
    # import mech_dpf
    # import Ans.DataProcessing as dpf
    # wf = dpf.Workflow(this.WorkflowId)
    # wf.Connect('contour_selector', value)
    # this.Evaluate()

def define_dpf_workflow(analysis):
    import mech_dpf
    import Ans.DataProcessing as dpf
    mech_dpf.setExtAPI(ExtAPI)
    dataSource = dpf.DataSources(analysis.ResultFileName)
    u = dpf.operators.result.displacement()
    nrm = dpf.operators.math.norm_fc()
    # timeScop = dpf.Scoping()
    # timeScop.Ids = [1]
    # u.inputs.time_scoping.Connect(timeScop)
    u.inputs.data_sources.Connect(dataSource)
    nrm.Connect(u)
    dpf_workflow = dpf.Workflow()
    dpf_workflow.Add(u)
    dpf_workflow.Add(nrm)
    dpf_workflow.SetOutputWarpField(u)
    # dpf_workflow.SetInputName(u, 0, 'time')
    # dpf_workflow.Connect('time', timeScop)
    dpf_workflow.SetOutputContour(nrm)
    dpf_workflow.Record('wf_id', False)
    this.WorkflowId = dpf_workflow.GetRecordedId()

Categories