How to include deformation scaling into a plot created by Python Result? By default it is unscaled
Rohith Patchigolla
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in Structures
By Adjusting Deformation scaling in Mechanical, one could scale the Deformed shape for any standard result. But, this doesn't seem to work for Python Result (scaling is greyed out).
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Answers
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One would just need to add the below line to the default code when one inserts Python result to deform the plot based on Deformation scaling.
dpf_workflow.SetOutputWarpField(u)
def post_started(sender, analysis):# Do not edit this line define_dpf_workflow(analysis) # Uncomment this function to enable retrieving results from the table/chart # def table_retrieve_result(value):# Do not edit this line # import mech_dpf # import Ans.DataProcessing as dpf # wf = dpf.Workflow(this.WorkflowId) # wf.Connect('contour_selector', value) # this.Evaluate() def define_dpf_workflow(analysis): import mech_dpf import Ans.DataProcessing as dpf mech_dpf.setExtAPI(ExtAPI) dataSource = dpf.DataSources(analysis.ResultFileName) u = dpf.operators.result.displacement() nrm = dpf.operators.math.norm_fc() # timeScop = dpf.Scoping() # timeScop.Ids = [1] # u.inputs.time_scoping.Connect(timeScop) u.inputs.data_sources.Connect(dataSource) nrm.Connect(u) dpf_workflow = dpf.Workflow() dpf_workflow.Add(u) dpf_workflow.Add(nrm) dpf_workflow.SetOutputWarpField(u) # dpf_workflow.SetInputName(u, 0, 'time') # dpf_workflow.Connect('time', timeScop) dpf_workflow.SetOutputContour(nrm) dpf_workflow.Record('wf_id', False) this.WorkflowId = dpf_workflow.GetRecordedId()
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